If a vector's magnitude is 32 units right and 28 units up, what's the approximate magnitude of a vector that's one-fourth the length of the first vector?

10.6 units

Step-by-step explanation:

First of all, let's find the magnitude of the first vector, which is given by the resultant of its two components:

units

The second vector has a length which is 1/4 of the length of the first vector, so it is

units

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

x=6 and x=3

beep beep imma sheep