If someone could explain how to do 17-19 that would be great i really am lost and if someone could give me a step by step but at this point any is good

17: see below.

18: x = 2; x = -2; x = 3i;  x = - 3i

19:  x = sqrt(3); x= - sqrt(3); x = 1 ; x = - 1

Step-by-step explanation:

17

Short answer No without doing anything. The 61 must be factorable using 6 as a factor. 61 is prime. But that's not really what you want to know although it is the answer. You look like you are doing synthetic division, so we'll answer it that way.

6 || 1    - 7     - 3      61

             6     -6      -54  

====================

     1      -1      -9        7

The answer is x^2 - x  - 9 with remainder of 7 / (x - 6)

18

x^4 + 5x^2 - 36 = 0

Substitute z for x^2

z^2 + 5z - 36 = 0   This factors.

(z + 9) (z - 4) = 0     Put the x^2 into the factors.

x^2 - 4 = 0              Add 4 to both sides  

x^2 = 4                   Take the square root of both sides.

x = +/- 2

===============

x^2 + 9 = 0

x^2 = - 9                      Take the square root of both sides

sqrt(x^2) = sqrt(-9)      

x = +/- 3i

19

19 is done exactly as 18 was done. You should get 4 real roots.

The graph is below. Very briefly it is going to factor as

(x^2 - 3)(x^2 - 1)

The results are x = sqrt(3); x= - sqrt(3); x = 1 ; x = - 1

proofs involving isosceles triangles often require special consideration because an isosceles triangle has several distinct properties that do not apply to normal triangles.(more about triangle types) therefore, when you are trying to prove that two triangles are congruent, and one or both triangles, are isosceles you have a few theorems that you can use to make your life easier.

step-by-step explanation:

an isosceles triangle has two congruent sides and two congruent angles. the congruent angles are called the base angles and the other angle is known as the vertex angle. ∠bac and ∠bca are the base angles of the triangle picture on the left. the vertex angle is ∠abc

8

step-by-step explanation: