The solution set of the equation ix-1i=3 is

x = - 2 or x = 4

Step-by-step explanation:

the expression inside the absolute value can be positive or negative

Removing the bars and solve x - 1 = ± 3

x - 1 = - 3 or x - 1 = 3

x - 1 = - 3 ( add 1 to both sides ) ⇒ x = - 2

x - 1 = 3 ( add 1 to both sides ) ⇒ x = 4

pls ask

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation