Answer before 2: 48 and i will mark you as brainliest match the reasons with the statements in the proof to prove that triangle abc is congruent to triangle abd, given that ab ⊥ bd, ab ⊥ bc, and ac = ad. given: ab ⊥ bd ab ⊥ bc ac = ad prove: △abc ≅ △abd 1. ab ⊥ bd, ab ⊥ bc, ac = ad reflexive property of equality 2. ∠abc and ∠abd are right angles hypotenuse - leg postulate 3. ab = ab perpendicular lines form right angles 4. △abc ≅ △abd given

3=log(n)=2

answer a: product property

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

grab rope, tie a loop-de-loop, put it around ur neck, now jump while its tied to a high place. now your shoes are cool.

step-by-step explanation:

you probably already have the answer but anyways it's b. 15.0

step-by-step explanation: