What is the remainder when the polynomial f(x)=3x^3-4x^2+2x+8 is divided by (x-5)

The remainder when the polynomial f(x) = 3x³ - 4x² + 2x + 8 is divided by (x - 5) is constant an equal f(5).

Substitute x = 5 to the polynomial:

(3x³ - 4x² + 2x + 8) : (x - 5) = q(x) + 293.

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.