A3 mi cab ride cost $3.00 . a 6 mi can ride cost $4.80 find a linear equation that modes cost c as a function of distance d.

c = 0.6d + 1.2

Step-by-step explanation:

Use distance as the independent variable and cost as the dependent variable. Each point (x, y) is (distance, cost).

The 3 mile ride for $3.00 gives you point (3, 3).

The 6 mile ride that cost $4.80 gives you point (6, 4.8).

Now you need to find the equation of the line that passes through points

(3, 3) and (6, 4.8).

y = mx + b

m = slope = (y2 - y1)/(x2 - x1) = (4.8 - 3)/(6 - 3) = 1.8/3 = 0.6

Use point (3, 3).

y = 0.6x + b

3 = 0.6(3) + b

3 = 1.8 + b

b = 1.2

The equation is

y = 0.6x + 1.2

Use c for cost and d for distance to get

c = 0.6d + 1.2

on monday rodney ate 1/4th of the sandwich = 3/12

on tuesday he ate 1/3rd of the sandwich = 4/12

therefore in total he has eaten = 3/12 + 4/12 = 7/12

thus we can say that he has eaten 7/12 of the sandwich on monday and tuesday alltogether.

happy to

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answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

hope this ^_^