Given sin θ = -1/2 and angle θ is in quadrant iv, what is the exact value of cos θ in its simplest form

Cos  θ = √3 / 2.

Step-by-step explanation:

The cosine si positive in quadrant IV.

Using the identity cos  θ = √(1 - sin^2 θ):

cos  θ = √(1 - (-1/2)^2)

= √ (3/4)

= √3 / 2

throw the computer

step-by-step explanation:

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic