A florist sells a bouquet of roses for $16 each and a bouquet of carnations
for $10 each. The shop sells 28 bouquets
today and makes $400. How many bouquets of
roses did the shop sell today and how many
bouquets of carnations were sold today?

Bouquets of roses = 20

Bouquets of carnations = 08

Step-by-step explanation:

Let,

x be the bouquets of roses sold

y be the bouquets of carnations sold

According to given statement;

x + y = 28       Eqn 1

16x + 10y = 400     Eqn 2

Multiplying Eqn 1 by 16

16(x+y=28)

16x + 16y = 448    Eqn 3

Subtracting Eqn 2 from Eqn 3

(16x+16y)-(16x+10y) = 448 - 400

16x + 16y - 16x - 10y = 48

6y = 48

Dividing both sides by 6

Putting y=8 in Eqn 1

x + 8 = 28

x = 28 - 8

x= 20

Hence,

Bouquets of roses = 20

Bouquets of carnations = 08

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5

where are the graphs?

step-by-step explanation: