Two captains need to be chosen from a fifteen person team. if the captain positions are identical, how many different ways can the two captains be selected?

In 105 different ways

Step-by-step explanation:

To solve this problem we will use combinations without repetitions.

C(n k) = V(n k) / k!

In this case n = 15 and k = 2

C(15 2) = V(15 2) / 2! = 15 · 14 / 2 = 15 · 7 = 105

The two captains can be selected in the 105 different ways (combinations).

God with you!!!

the revenue of the fitness center, y, is the product of two factors: the number of members and the fee paid by each member. there are 320 members now, but number of members goes down by 10 for each $5 increase in fees, so if x is the number of $5 price increases then members is equal to (320 - 10x). since the fee is currently $45, and the fee increases by $5 for every price bump x, the fee is given by (45 + 5x). so, revenue y is given by y = (320 - 10x)(45 + 5x).

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