Can someone me with number 6?

Hello from MrBillDoesMath!

p^4        + 4 p^3        + 5 p^2   -8p         -3

Discussion:

( p^4 + 3p^3  -2p + 1) + (p^3 + 5p^2 - 6p - 4) =>   combine like terms

p^4 ( 1 ) + p^3(3 + 1) + p^2(5) + p(-2-6) + (1-4)  =

p^4        + 4 p^3        + 5 p^2   -8p         -3

Thank you,

MrB

-232

step-by-step explanation:

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x