What is the argument of 3 - 3i? 300° 315° 330° 345°

315°

Step-by-step explanation:

z = a+bi

The modulus is the sqrt ( a^2 +b^2)

and the argument (I call it theta)  is equal to arctan (b/a)

We have z = 3-3i

We are looking for the argument of z

theta = arctan (-3/3)

           = -45 degrees

They don't like negative arguments so add 360 degrees to it.  It is the same value, we just loop once around the circle.

-45+360 =

315

f(x) is the value of the function. b is the value of the function when x equals zero or the y-coordinate of the point where the line crosses the y-axis in the coordinate plane.

step-by-step explanation:

hope this !

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )