The weekly revenue for a company is r = 3p^2 + 60p + 1060, where p is the price of the company's product. what price will result in a revenue of $1200.

1200 = 3p^2 + 60p + 1060

3p^2 + 60p - 140 = 0

x = (-60 ± √(60^2 - 4 * 3 * (-140))) / (2 * 3)

x = (-60 ± √(3600 + 1680)) / 6

x = (-60 ± √(5280)) / 6

x = (-60 ± 72.66) / 6

x1 = (-60 + 72.66) / 6 = 12.66 / 6 = 2.11$

The price will be 2.11$

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: