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Mathematics, 21.09.2019 13:30 19youngr

Evaluate 32y−3+53z\dfrac32y-3+\dfrac53z 2 3 y−3+ 3 5 z start fraction, 3, divided by, 2, end fraction, y, minus, 3, plus, start fraction, 5, divided by, 3, end fraction, z when y=6y=6 y=6 y, equals, 6 and z=3z=3 z=3 z, equals, 3 .

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Evaluate 32y−3+53z\dfrac32y-3+\dfrac53z 2 3 y−3+ 3 5 z start fraction, 3, divided by, 2, end fract...
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