Suppose maria places $5500 in an account that pays 2% interest compound each year. assume that no withdrawals are made from the account

follow the instructions below. do not do any rounding.

After 1 year:    $5,610

After 2 years: $5,722.20

Step-by-step explanation:

Use the formula for periodic compounding interest, which is

A = P(1 + r/n)^(nt), where A is the final amount, P is the initial deposit, r is the interest rate as a decimal, n is the number of times the interest is compounded per year, and t is how many years.

Here, P = 5,500, r = 0.02  (that's 2% as a decimal), n = 1,

t = 1 for the first answer, t = 2 for the second answer (1 year, then for 2 years)

Plug the known values in to solve...

For 1 year...

A = 5,500(1 + 0.02/1)^(1*1)

   A = 5,500(1.02)^1

      A = 5,610

For 2 years...

A = 5,500(1 + 0.02/1)^(1*2)

   A = 5,500(1.02)²

      A = 5,722.20

351°f

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)