What is the vertex for y=2(x+3)^2-6

(- 3, - 6)

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

y = 2(x + 3)² - 6 ← is in vertex form

with (h, k) = (- 3, - 6 ) ← vertex

  21.3

step-by-step explanation:

multiplying the given equation by c/sin(25°), we get

  c = 9/sin(25°) ≈ 21.2958 ≈ 21.3

we assume "c" is the length of ab, the side opposite angle c in triangle abc.

the answer will be the last one