Ineed immediately!40 points!

1) ray su is an angle bisector of ∠tsu is 42° what is the measure of ∠rst?

a) 24°
b) 84°
c) 168°
d) 42°

2) m is the midpoint of jk , jm = 4x + 1, and jk = 10x - 6. what is jm?

jm = ?

3) ray lc is an angle bisector of ∠jly , m∠jlc = (6x + 1)° , and m∠jly = (10x + 16)° .
what is m∠jlc?

∠jlc = ?

4) if quadrilateral aceg ≅ quadrilateral prmn, then which of the following it true?

a) —- —-
ce ≅ np

b) —- —-
ac ≅ mr

c) —- —-
ag ≅ mp

d) —- —-
eg ≅ mn

5) given that ∠bad ≅ ∠cda and ∠bda ≅ ∠cad, which theorem or postulate proves δacd ≅ δdba?

a) sas congruence postulate
b) asa congruence postulate
c) sss congruence postulate

6) given that bc ║ ef and bc ≅ fe , which theorem or postulate proves δbcd ≅ δfed?

a) sas congruence postulate
b) asa congruence postulate
c) not enough information to establish congruence
d) sss congruence postulate

7) which series of transformations result in the image of being congruent to the pre-image?

a) (x, y) → (x, -y)
(x, y) → (-x, y)
(x, y) → ( x+1, y-1)

b) (x, y) → (-x, -y)
(x, y) → (0.8x, 0.8y)
(x, y) → (x, y + 5)

c) (x, y) → (x+5, y+5)
(x, y) → (x, -y)
(x, y) → (2x, -y)

d) (x, y) → (3x, 3y)
(x, y) → (-x, y)
(x, y) → (x-4, y)

42

Step-by-step explanation:

RSU is also 42 because SU is the angle bisector so it divided RST in two equal halves.

Hope this helps :)

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!