Triangle abc and triangle pqr are given. triangle abc is congruent to triangle pqr by sas. if angle abc = 12x+2, angle pqr = 142-2x, ab = 5y+7, and pq = 3y-1, then which of the following statements are true? select all that apply

  x = 10, y = -1

Step-by-step explanation:

ΔABC ≅ ΔPQR  →  ∠B ≅ ∠Q    and     AB ≅ PQ

      ∠B ≅ ∠Q

12x + 2 = 142 - 2x

+2x                + 2x

14x + 2 = 142

       - 2     -2  

14x       = 140

÷14         ÷14  

    x       =  10

   AB ≅ PQ

3y - 1 = 5y + 1

-3y      -3y      

      -1 = 2y + 1

     -1         -1

     -2 = 2y

     ÷2   ÷2

      -1 = y

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

b

step-by-step explanation: