Suppose that there are two types of tickets to a show: advance and same-day. the combined cost of one advance ticket and one same-day ticket is $55. for one performance, 40 advance tickets and 15 same-day tickets were sold. the total amount paid for the tickets was $1325. what was the price of each kind of ticket?

advance tickets cost $20 each & same-day tickets cost $35 each

Step-by-step explanation:

Let cost of advanced ticket be x and cost of same-day ticket be y. Now we can write 2 equations and solve them simultaneously.

"The combined cost of one advance ticket and one same-day ticket is $55":

and

"...40 advance tickets and 15 same-day tickets were sold. The total amount paid for the tickets was $1325":

We solve for x in the first equation to get x = 55 - y and substitute this into 2nd equation and solve for y:

Now plugging in y = 35 into the first equation, we can solve for x:

Hence, advance tickets cost $20 each & same-day tickets cost $35 each

soo this can be solve by using the formula:

f = p( 1 + i)^ n

where f is the future profit

p is the initial profit

i is the percent increase

n is the number of years

a . f = 30000 ( 1.05)^n

b. f = 30000 ( 1.05)^15

f = $62,368