For number 81 and 84 it asks me to complete the square to form a perfect-square trinomial. could someone explain how i find the answers to these two questions?

To complete the square, you want to add a number that will allow the number to be factored into terms of the form (x + ?)^2

For x^2 + x + ?:
For (x + ?)(x + ?), we want both ? to add up the 1 (the number in front of x), and since both ? have to be the same number, ? must equal 1/2 (1/2 + 1/2 = 1).
Multiplying this out:
(x + 1/2)^2
(x + 1/2)(x + 1/2)
x^2 + x + 1/4

x^2 + x + 1/4

For x^2 + 6x + ?:
For (x + ?)(x + ?), we want both ? to add up the 6 (the number in front of x), and since both ? have to be the same number, ? must equal 3 (3 + 3 = 6). 
Multiplying this out:
(x + 3)^2
(x + 3)(x + 3)
x^2 + 6x + 9

 x^2 + 6x + 9

Completeing the square in form ax^2+b+c=0 1st move c to other side or ignore it if not present 2nd. make sure a=1, if not, divide both sides by a 3rd divide b by 2 and squaer that ((b/2)^2) and add that to both sides factor perfect square 81. ignore c a=1 so good b=1 so 1/2, then squaer that which is 1/4 that is the blank space 1/4 84. ignore c since not present a is equal to 1 b=6 so 1/2 of that is 3, 3^2=9 9 is the blank 81. blank is 1/4 84. blank is 9

I'm not sure exactly but my best guess would be 1/4