You have a cone with a radius of 8 ft and a height of 10 ft. find the area of the triangle formed by a perpendicular cross-section through the cone’s center.

80ft²

Step-by-step explanation:

Given in the question,

radius of cone's base = 8ft

              cone's base = base of triangle

height of cone = 10 ft

height of cone = height of triangle

Area = 1/2(h)(b)

here h = height of triangle

        b = base of triangle

A = 1/2(8)(10)

A = 40ft²

Since the section is 2 similar triangles back to back around the vertical centre so the area cross sectional area of triangle form in the cone is 2(40)ft² = 80ft²

he spend 5.1 minutes chatting with his friends

step-by-step explanation:

2/5+1/2=9/10

6/1-9/10=5 1/10