K= n times n + 9n +1

mo says;
" k will be a prime number for all integer values of 'n' from 1 to 9"

show that mo is wrong.
you must show that your value "k" is not prime.

k = n(n^2 +9n+1)

expand brackets

k = n^3 + 9n^2 + n

first subsitute 1 as n to see if the result is prime.

k = (1)^3 + 9(1)^2 + 1

k = 1 + 9 + 1

k = 11 (this number is prime)

then substitute 2

k = (2)^3 + 9 (2)^2 + 2

k = 8 + 9 (4) + 2

k = 36 + 10

k = 46 (THIS NUMBER IS NOT PRIME SO MO IS WRONG)

a = 3.14

b = 18

c = 18/5 or 3.6 or 3 3/5

step-by-step explanation: