Amajor newspaper conducted a random survey of 1,800 of its 75,000 subscribers. the subscribers were asked if the paper should increase its coverage of national news. out of the 1,800 in the sample, 594 responded that they want more national news.
construct a 95% confidence interval (z*-score = 1.96) for the proportion of subscribers who would like more national news coverage.
complete the statements.

the estimated population proportion, , is %.

when the margin of error is calculated using the

formula e = z* , to the nearest tenth of a percent, the result is %.
with 95% confidence, it can be said that the proportion of subscribers who would like more coverage of national news is between % and %

33%

2.2%

30.8%

35.2%

Step-by-step explanation:

Step-by-step explanation:

Given that a  major newspaper conducted a random survey of 1,800 of its 75,000 subscribers.

The sample proportion  of subscribers who would like more national news coverage.=

Hence

a) The estimated population proportion, , is _33__%.

b)

When the margin of error is calculated using the ___formula

E =

=

c) With 95% confidence, it can be said that the proportion of subscribers who would like more coverage of national news is between _0.33-0.0326_=29.74_% and __0.33+0.0326=36.26_%

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*