If p varies directly as r and p=4,r=2,what the value of r when p=12

r = 6

Step-by-step explanation:

Given that p varies directly as r, then the equation relating them is

p = kr ← k is the constant of variation

To find k use the condition p = 4, r = 2

k = = = 2

p = 2r ← equation of variation

When p = 12

12 = 2r ( divide both sides by 2 )

hence r = 6

x^6

step-by-step explanation:

this is correct because:

x-6=0

0*x=0

so

x^6

x/3-10=8

x/3=18

x=48