Which equation has an a-value of –2, a b-value of 1, and a c-value of 3? 0 = –2x2 + x + 3 0 = 2x2 + x + 3 0 = –2x2 + 3 0 = 2x2 – x + 3

ax² + bx + c = 0

You know:

a = -2

b = 1

c = 3

The 1st option is your answer

-2x² + x + 3 = 0

a = -2

b = 1

c = 3

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°