Two urns contain white balls and yellow balls. the first urn contains 10 white balls and 6 yellow balls and the second urn contains 8 white balls and 3 yellow balls. a ball is drawn at random from each urn. what is the probability that both balls are white?

5/11

Step-by-step explanation:

These are two independent events, because no matter which color the ball picked from jar #1 it will not affect the draw in jar #2.  

To evaluate the probability of both balls to be white, we first need to evaluate the probability of each draw resulting in a white ball then multiply those probabilities.

First urn: 10 white, 6 yellow balls

Chances to get a white ball: 10/16, or 5/8.

Second urn: 8 white, 3 yellow balls

Chances to get a white ball: 8 / 11

Chances for both balls to be white:

5/8 * 8/11 = 5/11

step-by-step explanation:

what are the statements? and what do you mean by "216 2 1 6"?

answer: you need to organize this better it does not make sense.

step-by-step explanation: ?