The2,8 slope =4; (2,8) is on the line write the equation

The equation of the line is y = 4x

Step-by-step explanation:

* Lets revise how to form an equation of a line from its slope and

 a point on the line

- The equation of a line is written as y = mx + b where m is the

  slope of the line and b is the y-intercept.

- The line intersect the y-axis at point (0 , b)

* Lets solve the problem

- The line has slope = 4

- The line passes through the point (2 , 8)

∵ The slope = 4

∵ m is the slope of the line in the equation

∴ m = 4

- Substitute the value of m in the equation

∵ y = mx + b

∴ y = 4x + b

- To find the value of b substitute the x-coordinate and the

  y-coordinate of the point instead of x and y of the equation

∵ The point (2 , 8) lies on the line

∵ y = 4x + b

- Put x = 2 and y = 8 in the equation to find b

∴ 8 = 4(2) + b ⇒ simplify

∴ 8 = 8 + b ⇒ subtract 8 from both sides

∴ 0 = b

- That means the y-intercept = 0 and the line passing through

  the origin point

∴ y = 4x + 0

* The equation of the line is y = 4x

i do not know this sorry : (