Acircle with radius r is inscribed into a right triangle. find the perimeter of the triangle if: the length of the hypotenuse is 24 cm, and r=4 cm;

56 cm

Step-by-step explanation:

The tangents from the 90° angle will form a square with the radii that has a side length of 4. If we call the length of the short side of the right triangle "x", then the tangent lengths are ...

on the short side of the triangle: 4, x-4

on the hypotenuse side of the triangle: x-4, 24-(x-4) = 28-x

on the long side of the triangle: 4, 28-x

The perimeter is twice the sum of the unique tangent lengths:

P = 2(4 + (x-4) + (28-x)) = 2·28

P = 56 . . . . . the perimeter is 56 cm.

Using the Pythagorean theorem on side lengths x and 32-x and hypotenuse 24, we find x = 16-4√2 ≈ 10.34, the length of the short side (in cm).

answer:  

step-by-step explanation:

here x represents the height of the pole,

and, the height of the shadow of the pole is 12 feet.

also, the angle of elevation from the top of the pole is 40°,

therefore,

by the low of sine,

which is the required equation for finding the value of x,