Write an equation of an ellipse in standard form with the center at the origin and a height of 12 units and width of 19 units.

The equation of the ellipse in standard form is 4x²/361 + y²/36 = 1

Step-by-step explanation:

* Lets revise the equation of the ellipse

- The standard form of the equation of an ellipse with center (0 , 0 )  

  and major axis parallel to the x-axis is x²/a² + y²/b² = 1  

# a > b  

- The length of the major axis is 2a  

- The coordinates of the vertices are ( ± a , 0 )  

- The length of the minor axis is 2b  

- The coordinates of the co-vertices are ( 0 , ± b )  

- The coordinates of the foci are ( ± c , 0 ) , where c ² = a ² − b²  

* Lets solve the problem

∵ The center of the ellipse is (0 ,0)

∵ Its width is 19 units

∴ The length of the major axis is = 19

∴ 2a = 19 ⇒ divide both sides by 2

∴ a = 19/2 ⇒ ∴ a² = 361/4

∵ Its height is 12 units

∴ The length of the minor axis is = 12

∴ 2b = 12 ⇒ divide both sides by 2

∴ b = 12/2 = 6 ⇒ ∴ b² = 36

- Lets write the equation in standard form

∵ The equation is x²/a² + y²/b² = 1

∴ x²/(361/4) + y²/36 = 1 ⇒ simplify it

∴ 4x²/361 + y²/36 = 1

* The equation of the ellipse in standard form is 4x²/361 + y²/36 = 1