We are creating a new card game with a new deck. unlike the normal deck that has 13 ranks (ace through king) and 4 suits (hearts, diamonds, spades, and clubs), our deck will be made up of the following. each card will have: i) one rank from 1 to 15. ii) one of 9 different suits. hence, there are 135 cards in the deck with 15 ranks for each of the 9 different suits, and none of the cards will be face cards! so, a card rank 11 would just have an 11 on it. hence, there is no discussion of "royal" anything since there won't be any cards that are "royalty" like king or queen, and no face cards! the game is played by dealing each player 5 cards from the deck. our goal is to determine which hands would beat other hands using probability. obviously the hands that are harder to get (i. e. are more rare) should beat hands that are easier to get. a) how many different ways are there to get any 5 card hand?

i believe that the slope of the line is -5

step-by-step explanation:

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.