You invest $3000 in an account at 3.5% per year simple interest. how much will you have in the account at the beginning of the 7th year? round your answer to the nearest whole dollar. a. $3735 b. $3720 c. $3540 d. $3630

Option "D" is correct $3630

Step-by-step explanation:

At the beginning of the 7th year, the money has been in the account for 6 years.

The simple interest on $3000 at 3.5% for 6 years is I = prt:

(3000) = (.035) = (6) = 360

he amount in the account at the beginning of the 7th year is then the original amount plus the interest $3630.

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752