Answer quickly , will mark brainliest (50 points) question: a diameter of a circle has endpoints p(-10,2) and q(4,6) a. find the center of the circle. b. find the radius. if your answer is not an integer express it in radical form. c. write an equation for the circle.

a. The Center   has coordinates (-10)+4)/2 and (-2+6) / 2 =  (-3, 2)

b. The radius is the distance of the center from  Q:-

= sqrt (4 - -3)^2  +  (6-2)^2))

= sqrt 65

c .   Equation of a circle  is

 (x - a)^2 + (y - b)^2 = r^2  where (a, b) is the center and r = the radius so our circle has the equation:-

(x + 3)^2 + (y - 2)^2 = 65

Hope this helps! :)

let x and 400 - x be the two numbers.  

==> 0.80x + 0.85(400 - x) = 400 - 68 from the statement of the problem.  

< ==> 0.80x + 0.85(400 - x) = 400 - 68  

==> 340 - 0.05x = 332  

< ==> -0.05x = -8 ==> x = 160, the first number ==> 400 - x = 240, the second number.