Find the solutions of the systemy=x^2+3x-4y=2x+2a. (-3,6) and (2,-4)b. (-3,-4) and (2,6)c. (-3,-4) and (-2,-2)d. no solution

b. (-3, -4) and (2, 6)

Step-by-step explanation:

By the transitive property of equality, if y equals thing 1 and y also equals thing 2, then thing1 and thing 2 are also equal.  So we will set them equal to each other and factor to solve for the 2 values of x:

Get everything on one side of the equals sign, set the whole mess equal to 0, and combine like terms to get:

Because this is a second degree polynomial, a quadratic to be precise, it has 2 solutions.  We need to find those 2 values of x and then use them in either one of the original equations to solve for the y values that go with each x.  

Factoring that polynomial above gives you the x values of x = -3 and 2.  Sub in -3 first:

y = 2(-3) + 2 and

y = -6 + 2 so

y = -4

Therefore, the coordinate is (-3, -4).

Onto the next x value of 2:

y = 2(2) + 2 and

y = 4 + 2 so

y = 6

Therefore, the coordinate is (2, 6)

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

1. sometimes

2. never true

3. sometimes

step-by-step explanation:

these are pretty self explanatory if you know what supp right and com angles are