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![\sqrt[2]{x}=x^{\frac{1}{2}}](/tpl/images/0009/2020/9e292.png)
![\sqrt[2]{16x^{36}}=\sqrt[2]{4^2x^{18\cdot2}}](/tpl/images/0009/2020/89024.png)
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What is the square root of 16x^ 36?...
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Computers and Technology, 06.03.2020 23:32
