A={{1,-1,0,0},{2,-1,0,0},{0,0,1,0}, {-1,-1,0,1}} ofis ?(s) .a. ax=0. a −1c. a is . a is .e. of

The correct answer is:

                   Option: E

   E.   None of the above

has infinite many solutions if det(A)=0

and is non-singular or invertible otherwise i.e. when det(A)≠0

The matrix that will be formed by the given set of vectors is:

Also, determinant i.e. det of matrix A is calculated by:

Hence, determinant is not equal to zero.

This means that the matrix is invertible and non-singular.