Two catalysts may be used in a batch chemical process. twelve batches were prepared using catalyst 1, resulting in an average yield of 85 and a sample standard deviation of 3. fifteen batches were prepared using catalyst 2, and they resulted in an average yield of 91 with a standard deviation of 2. assume that yield measurements are approximately normally distributed with the same standard deviation. (a) is there evidence to support the claim that catalyst 2 produces higher mean yield than catalyst 1? use alpha = 0.01. (b) find a 99% confidence interval on the difference in mean yields that can be used to test the claim in part (a). (e. g. 98.76). mu_1 - mu_2 lessthanorequalto the tolerance is +/-2%

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

step-by-step explanation:

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation: