∀x((cube(x) ∧ large(x)) → frontof(x, a))
∃x(large(x) ∧ ¬frontof(x, a))
∃x ¬cube(x)
...
Mathematics, 17.07.2019 18:30 gabmilex1
∀x((cube(x) ∧ large(x)) → frontof(x, a))
∃x(large(x) ∧ ¬frontof(x, a))
∃x ¬cube(x)
i am using fitch to solve this proof. for the life of me i can't figure it out.
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