Pierre sold 340 tickets for a concert. balcony tickets cost $5 while tickets for the lower floor cost $10. if pierre sold $2,700 worth of tickets, how many lower floor tickets did he sell?

He sold 200 lower floor tickets.

Step-by-step explanation:  

Consider the provided information.

Pierre sold 340 tickets for a concert.

Let Balcony tickets represents by x and lower floor ticket represents by y.

As we know he sold 340 tickets in total, i.e.

x + y = 340 (1)

Balcony tickets cost $5 while tickets for the lower floor cost $10.

If he sold x balcony tickets, so the money he got after selling x balcony tickets is 5x. Similarly, If he sold y lower floor tickets, so the money he got after selling y lower floor tickets is 10y.

Pierre sold $2,700 worth of tickets, i.e.

5x + 10y = 2700 (2)

Now use elimination method to solve the system of equations:

Multiply the equation (1) with 5 and subtract them as shown below:

5x + 5y = 1700

5x + 10y = 2700

-5y = -1000

  y = 200

Thus, he sold 200 lower floor tickets.

step-by-step explanation:

i'm pretty sure it would take 20 hours because it's half the men so you multiply the number of hours it takes by 2

what? that isnt a question

step-by-step explanation: