Suppose you just received a shipment of eleven televisions. three of the televisions are defective. if two televisions are randomly selected, compute the probability that both televisions work. what is the probability at least one of the two televisions does not work?

 The probability that both televisions work : 0.5329

The  probability at least one of the two televisions does not work : 0.4671

Step-by-step explanation:

Given : The total number of television : 11

The number of defective television : 3

The probability that the television is defective :

Binomial distribution formula :-

, where P(X) is the probability of getting success in x trials, p is the probability of success and n is the total trials.

If two televisions are randomly selected, then the probability that both televisions work:

The probability at least one of the two televisions does not work :

ok so the answer to your question is simple as long as you look at the different dimensions that contain the exemplary letters that combined in the right order give you words that eventually within the 5th dimension will conform and give you the correct answer to your question. hope i , stop looking at this easily, look at it with a spectral view.

step-by-step explanation:

told you

it is 28 degrees colder in detroit than philadelphia.

step-by-step explanation:

what number adds to 21

-7 + ? = 21

-7 + 28 = 21

hope it