Worth lots of extra points + a friend if you answer two stoves were turned off at the same time, and they both started to cool down. the following equation gives the temperature of the first stove (in degrees celsius) as a function of time (in minutes) t= 180 - 1.55m the graph of the temperature of the second stove (in degrees celsius) as a function of time (in minutes) is shown below. which stove started at a higher temperature? a. first stove b. second stove c. the stove started at the same temperature which stove cooled down at a greater rate? a. first stove b. second stove c. the stoves cooled done at same rate

B for both

Step-by-step explanation:

The answer is B for both questions. I know this because it's a Khan Academy question and I solved it to help ya out :)

B

Step-by-step explanation:

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following