v=4/3? r^2 suppose that, for the sphere in the video, instead of being told how fast the radius is changing, we're told that the volume is increasing at a constant rate of dv/dt=4 cubic centimeters per second. how fast is the radius increasing at the instant when the radius is r=10 centimeters? dr/dt= centimeters per second.
instead of thinking about the volume, suppose that we are interested in how the surface area of the sphere is changing. use the surface area formula s=4? r^2 to determine how fast the surface area is changing at the instant when the radius is r=20 cm and the radius is increasing at dr/dt=2 centimeters per second. ds/dt=
how to get this answer?