The length of a rectangle is 2cm more than four times the width. if the perimeter of the rectangle is 84 cm, what are it’s dimensions?

x=36;y=8.

Step-by-step explanation:

x=length

y=width

the length of a rectangle is 2cm more than four times the width.

so,

x=2+4y(1)

now,

the perimeter of the rectangle is 84 cm

so,

2(x+y)=84

x+y=42(2)

2+4y+y=42

5y=40

y=8(3)

so,

x=42-8             [from 2 & 3]

x=36

w=8    L = 34

Step-by-step explanation:

P=2W+2L

L=4W+2

2W + 2(4W+2) = 84

2W + 8W +4 =84

10W=80

w=8

L=(8*4+2)=34        

2(8) +2(34) = 16+ 68 = 84

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the answer is false

step-by-step explanation:

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