Find the equation of the sphere of radius 8 that lies above the xy-plane that just touches the xy-plane at the point (3, −2, 0).

Step-by-step explanation:

We are given that a sphere of radius 8 that lies above the xy-plane and a sphere just touches the xy-plane at the point (3,-2,0).

We have to find the equation of sphere

We know that distance between the center (h,k,l)of sphere and the point (3,-2,0) lies on the sphere is equal to radius of sphere.

Therefore, the center of sphere is at(3,-2,8)

Equation of sphere with center (h,k,l) and radius r

Substitute the values then we get

Hence,the required equation of sphere

y=mx+

the aswere is the one with all 8's and the second one is with the 10,8 and 6

step-by-step explanation: