Find the polar coordinates of the following points given in cartesian coordinates. (2√2, 2√2)

r = 4,

theta = pi/4

Step-by-step explanation:

A cartesian pair (x,y) will have the following polar coordinates:

[tex]r = \sqrt(x^2 + y^2)[\tex]

theta = arctan(y/x)

So for your pair:

[tex]r =  \sqrt{(2\sqrt{2})^2 + (2\sqrt{2})^2} [\tex]

[tex]r = \sqrt{8+8} [\tex]

[tex]r = \sqrt{16} [\tex]

r = 4.

--------------------------

theta = arctan(1)

What is the angle that has tan = 1? It is pi/4. So arctan(1) = pi/4 = theta

---------------------------

what is all that apply?

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.