Use the gcf of 48 and 30 to write the sum of the two numbers as the product of their gcf and another sum
+ = +_) =
_= blank space

GCF of numbers is the highest number that can divide both numbers. The expression for the sum of 48 and 30 is:

The numbers are given as 48 and 30

So, the expression is

Their GCF is 6. So, we have:

Factor out 6

Solve the expression in brackets

Evaluate the product

Hence, the expression is:

Read more about GCF at:

link

Step-by-step explanation:

48 = 6 · 8

30 = 6 · 5

48 + 30 = 6(8) + 6(5) = 6(8 + 5) = 6(13)

Distributive property: a(b + c) = ab + ac

48 = 2 · 2 · 2 · 2 · 3

30 = 2 · 3 · 5

GCF(48, 30) = 2 · 3 = 6

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

37

step-by-step explanation: