What is the equation of the line that is parallel to the line 5x + 2y = 12 and passes through the point (−2, 4)? y = – five-halvesx – 1 y = – five-halvesx + 5 y = two-fifthsx – 1 y = two-fifthsx + 5

Step-by-step explanation:

the line equation is  5x + 2y = 12

Solve for y to find out slope m

y=mx+b

Subtract 5x from both sides

Divide both sides by 2

slope = -5/2

Slope of parallel lines are same . So slope of parallel line is

m=-5/2 , point (-2,4)

Add 4 on both sides

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation