Find four consecutive multiples of 5 whose sum is 90

15, 20, 25, 30

Step-by-step explanation:

If want to find the first multiple, we could actually use the equation: x + (x+5) + (x+5+5) + (x+5+5+5) = 90. After simplifying this term, we would get 4x+30 = 90 which then transforms into 4x=60 which simplifys to x = 15. Plug 15 into the original equation, and you would get the multiples 15 + 20 + 25 + 30 = 90.

The answer is 15, 20, 25, and 30

We know that you need to have a multiple of 5. The sum is 90. First divide 90 by something. Let's start with 15. It is a multiple of 5. You can divide by 90. Now do the same thing again. Then, eventually, you would get 15, 20, 25, and 30 is the answer.

too hard the other guy did it

step-by-step explanation:

irrational, then, just means all the numbers that aren't rational. every integer is a rational number, since each integer n can be written in the form n/1. however, numbers like 1/2, 45454737/2424242, and -3/7 are also rational, since they are fractions whose numerator and denominator are integers.

step-by-step explanation: