What are the solutions of the compound inequality 2d + 3 ≤ –11 or 3d – 9 > 15?
a. d ≤ –7 or d > 8
b. d ≤ –4 or d > 2
c. d ≤ –7 or d > 2
d. d ≤ –4 or d > 8

A. d ≤ –7 or d > 8.

Step-by-step explanation:

Given  : 2d + 3 ≤ –11 or 3d – 9 > 15.

To find : What are the solutions of the compound inequality .

Solution : We have given 2d + 3 ≤ –11 or 3d – 9 > 15.

For  2d + 3 ≤ –11

On subtracting both sides by 3

2d  ≤ –11 - 3 .

2d  ≤ –14.

On dividing both sides by 2 .

d  ≤ –7.

For  3d – 9 > 15.

On adding both sides by 9.

3d > 15 + 9 .

3d > 24 .

On dividing both sides by 3 .

d > 8 .

So, A. d ≤ –7 or d > 8.

Therefore,  A. d ≤ –7 or d > 8.

i believe the correct answer is option 4.principalities were small territories that were run by russian rulers.

which statement correctly defines principalities in northern asia in the 1200s? principalities were small territories that were run by russian rulers.

hope i could ! : )

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