Chapter 3 probability add and mult with one method of a procedure called acceptance sampling, a sample of items is randomly selected without replacement and the entire batch is accepted if every item in the sample is okay. the abc electronics company has just manufactured 2100 write-rewrite cds, and 160 are defective. if 5 of these cds are randomly selected for testing, what is the probability that the entire batch will be accepted? rounded to four decimal place accuracy.

The probability that the entire batch will be accepted is 67.25%

Step-by-step explanation:

First, knowing that there are 160 defective CDs, we can calculate the probability that taking only one CD, it is not defective:

Total - Defective = Okay

2100 - 160 = 1940

(92.38%)

Then, in the same way, we calculate the probability if we take 5 CD's of the sample, taking into account that every time I take out one I will have one less in the total, and also one less that is Okay:

(67.25%)

answer: 0.95, d

step-by-step explanation:

first, you have to combine the percentages of costumers ordering pizza or salad. 25% (percent of salads ordered) plus 70% (percent of pizzas ordered) is equal to 95%. then, turn 95% into a fraction: 95/100. lastly, divide 95 by 100 and you will get 0.95, d.

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )