What is the value of (g o )

f(x)=2x+7; g(x)=3x+12

(g o f)(-6) = -3

Step-by-step explanation:

f(x)=2x+7; g(x)=3x+12

(g o f)(-6) = g(f(-6))

but f(-5) = 2(-6)+7 = -5

(g o f)(-6) = g(f(-6))  = g(-5) = 3(-5)+12 = - 3

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse