2dice are rolled. what is the probability that the sum of the numbers rolled is a number greater than or eaqual to 5

2 + 3 = 5 > = 5;
2 + 4 = 6 > =5;
2 + 5 = 7 >= 5;
2 + 6 = 8 >= 5;
3+2 = 5 >= 5;
3 + 3 = 6  >= 5;
3 + 4 = 7  >= 5;
3 + 5 = 8  >= 5;
3 + 6 = 9  >= 5;
4+1 = 5  >= 5;
4+2 = 6  >= 5;
4+3 = 7  >= 5;
4+4 = 8  >= 5;
4+5 = 9  >= 5;
4+6 = 10  >= 5;
5+1 = 6  >= 5;
5+2 = 7  >= 5;


6 + 6 = 12  >= 5;

Number of ways it can happen = 27;

Total number of outcomes = 6*6 = 36;

Probability of an event happening = Number of ways it can happen / Total number of outcomes => Probability = 27/36 = 0.75;

Using the rise/run rule. you would get 2/6.simp. 1/3